What is -2x^2-2y^2+4x-16y+2=0 ?

The solution to -2x^2-2y^2+4x-16y+2=0 is Circle with (a,b)=(1,-4),r=3sqrt(2)

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-2x^2-2y^2+4x-16y+2=0

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

(a, b) = (1, - 4), r = 32

Solution steps

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

Rewrite

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 4))^{2} = (32)^{2}

Therefore the circle properties are:

(a, b) = (1, - 4), r = 32

x^{2} + y^{2} - 10 x - 2 y - 74 = 0

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

4 x^{2} + 4 y^{2} - 32 y + 39 = 0

x^{2} + 12 x + y^{2} - 12 y = - 56

(x - 1)^{2} + (y + 6)^{2} \leq 4

What is -2x^2-2y^2+4x-16y+2=0 ?
The solution to -2x^2-2y^2+4x-16y+2=0 is Circle with (a,b)=(1,-4),r=3sqrt(2)