What is 8-9(x^2+y^2)=9(x^2+y^2) ?

The solution to 8-9(x^2+y^2)=9(x^2+y^2) is Circle with (a,b)=(0,0),r= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8-9(x^2+y^2)=9(x^2+y^2)

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

(a, b) = (0, 0), r = \frac{2}{3}

Solution steps

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

Rewrite

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{2}{3}

a^{2} + b^{2} + 0.02 = 1

x^{2} + y^{2} + 4 x + 0 y + 3 = 0

(x - 3)^{2} + y^{2} = 3

(x - 3)^{2} + y^{2} = 6

x^{2} - 8 x + y^{2} + 6 y + 16 = 0

What is 8-9(x^2+y^2)=9(x^2+y^2) ?
The solution to 8-9(x^2+y^2)=9(x^2+y^2) is Circle with (a,b)=(0,0),r= 2/3