What is (x-3)^2+y^2=3 ?

The solution to (x-3)^2+y^2=3 is Circle with (a,b)=(3,0),r=sqrt(3)

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(x-3)^2+y^2=3

(x - 3)^{2} + y^{2} = 3

(a, b) = (3, 0), r = 3

Solution steps

(x - 3)^{2} + y^{2} = 3

Rewrite

(x - 3)^{2} + y^{2} = 3

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 3

(x - 3)^{2} + y^{2} = 6

x^{2} - 8 x + y^{2} + 6 y + 16 = 0

(y - 10)^{2} + (x - 10)^{2} = 5^{2}

(x - 7)^{2} + (y + 4)^{2} = 25

(x - 9)^{2} + y^{2} = 10

What is (x-3)^2+y^2=3 ?
The solution to (x-3)^2+y^2=3 is Circle with (a,b)=(3,0),r=sqrt(3)