What is (x+4)^2+(y-6)^2= 6/2 ?

The solution to (x+4)^2+(y-6)^2= 6/2 is Circle with (a,b)=(-4,6),r=sqrt(6/2)

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(x+4)^2+(y-6)^2= 6/2

(x + 4)^{2} + (y - 6)^{2} = \frac{6}{2}

(a, b) = (- 4, 6), r = \frac{6}{2}

Solution steps

(x + 4)^{2} + (y - 6)^{2} = \frac{6}{2}

Rewrite

(x + 4)^{2} + (y - 6)^{2} = \frac{6}{2}

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 6)^{2} = (\frac{6}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 4, 6), r = \frac{6}{2}

xx + y^{2} = 5

(x - 0)^{2} + (y - 1)^{2} = 1

(x - \frac{3}{5})^{2} + (y + \frac{7}{8})^{2} = \frac{9}{4}

x^{2} + y^{2} - 4 x + 5 y - 5 = 0

x^{2} + x + y^{2} - \frac{1}{2} y = \frac{1}{4}

What is (x+4)^2+(y-6)^2= 6/2 ?
The solution to (x+4)^2+(y-6)^2= 6/2 is Circle with (a,b)=(-4,6),r=sqrt(6/2)