What is (x-3/5)^2+(y+7/8)^2= 9/4 ?

The solution to (x-3/5)^2+(y+7/8)^2= 9/4 is Circle with (a,b)=(3/5 ,-7/8),r= 3/2

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(x-3/5)^2+(y+7/8)^2= 9/4

(x - \frac{3}{5})^{2} + (y + \frac{7}{8})^{2} = \frac{9}{4}

(a, b) = (\frac{3}{5}, - \frac{7}{8}), r = \frac{3}{2}

Solution steps

(x - \frac{3}{5})^{2} + (y + \frac{7}{8})^{2} = \frac{9}{4}

Rewrite

(x - \frac{3}{5})^{2} + (y + \frac{7}{8})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - \frac{3}{5})^{2} + (y - (- \frac{7}{8}))^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{5}, - \frac{7}{8}), r = \frac{3}{2}

x^{2} + y^{2} - 4 x + 5 y - 5 = 0

x^{2} + x + y^{2} - \frac{1}{2} y = \frac{1}{4}

(x - 7)^{2} + (y - 3)^{2} = 4

5 x^{2} + 5 y^{2} + 100 x + 50 y + 220 = 0

x^{2} + y^{2} \leq 4 x

What is (x-3/5)^2+(y+7/8)^2= 9/4 ?
The solution to (x-3/5)^2+(y+7/8)^2= 9/4 is Circle with (a,b)=(3/5 ,-7/8),r= 3/2