What is (x-7)^2+(y-3)^2=4 ?

The solution to (x-7)^2+(y-3)^2=4 is Circle with (a,b)=(7,3),r=2

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(x-7)^2+(y-3)^2=4

(x - 7)^{2} + (y - 3)^{2} = 4

(a, b) = (7, 3), r = 2

Solution steps

(x - 7)^{2} + (y - 3)^{2} = 4

Rewrite

(x - 7)^{2} + (y - 3)^{2} = 4

in the form of the standard circle equation

(x - 7)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (7, 3), r = 2

5 x^{2} + 5 y^{2} + 100 x + 50 y + 220 = 0

x^{2} + y^{2} \leq 4 x

3 x^{2} + 3 y^{2} - 24 x - 24 y - 51 = 0

(x - (- 2))^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} \leq 64

What is (x-7)^2+(y-3)^2=4 ?
The solution to (x-7)^2+(y-3)^2=4 is Circle with (a,b)=(7,3),r=2