What is x^2+y^2+2x+4y=9 ?

The solution to x^2+y^2+2x+4y=9 is Circle with (a,b)=(-1,-2),r=sqrt(14)

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x^2+y^2+2x+4y=9

x^{2} + y^{2} + 2 x + 4 y = 9

(a, b) = (- 1, - 2), r = 14

Solution steps

x^{2} + y^{2} + 2 x + 4 y = 9

Rewrite

x^{2} + y^{2} + 2 x + 4 y = 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 2))^{2} = (14)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 2), r = 14

x^{2} + y^{2} + 2 x + 4 y = 8

y = x^{(2)} - 4 x + y^{(2)}

x^{2} - 6 x + y^{2} = 16

4 x^{2} + 8 x + 4 y^{2} + 4 = 16

x^{2} - \frac{5}{2} x + (y + 2)^{2} = 50

What is x^2+y^2+2x+4y=9 ?
The solution to x^2+y^2+2x+4y=9 is Circle with (a,b)=(-1,-2),r=sqrt(14)