What is x^2-5/2 x+(y+2)^2=50 ?

The solution to x^2-5/2 x+(y+2)^2=50 is Circle with (a,b)=(5/4 ,-2),r=(5sqrt(33))/4

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x^2-5/2 x+(y+2)^2=50

x^{2} - \frac{5}{2} x + (y + 2)^{2} = 50

(a, b) = (\frac{5}{4}, - 2), r = \frac{5 33}{4}

Solution steps

x^{2} - \frac{5}{2} x + (y + 2)^{2} = 50

Rewrite

x^{2} - \frac{5}{2} x + (y + 2)^{2} = 50

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - (- 2))^{2} = (\frac{5 33}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, - 2), r = \frac{5 33}{4}

4 = x^{2} + y^{2} - 2 x + 4 y

(x - 12)^{2} + (y + 7)^{2} = 961

(x + 4)^{2} + (y + 1)^{2} = 100

(x - 8)^{2} + (y - 6)^{2} = 1^{2}

x^{2} + (y - \frac{25}{3})^{2} = 144

What is x^2-5/2 x+(y+2)^2=50 ?
The solution to x^2-5/2 x+(y+2)^2=50 is Circle with (a,b)=(5/4 ,-2),r=(5sqrt(33))/4