What is (x-12)^2+(y+7)^2=961 ?

The solution to (x-12)^2+(y+7)^2=961 is Circle with (a,b)=(12,-7),r=31

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(x-12)^2+(y+7)^2=961

(x - 12)^{2} + (y + 7)^{2} = 961

(a, b) = (12, - 7), r = 31

Solution steps

(x - 12)^{2} + (y + 7)^{2} = 961

Rewrite

(x - 12)^{2} + (y + 7)^{2} = 961

in the form of the standard circle equation

(x - 12)^{2} + (y - (- 7))^{2} = 3 1^{2}

Therefore the circle properties are:

(a, b) = (12, - 7), r = 31

(x + 4)^{2} + (y + 1)^{2} = 100

(x - 8)^{2} + (y - 6)^{2} = 1^{2}

x^{2} + (y - \frac{25}{3})^{2} = 144

\frac{x ^{2}}{15} + \frac{y ^{2}}{15} - \frac{2 x}{15} - \frac{6}{15} = 0

(x - 7)^{2} + (y + 13)^{2} = 81

What is (x-12)^2+(y+7)^2=961 ?
The solution to (x-12)^2+(y+7)^2=961 is Circle with (a,b)=(12,-7),r=31