What is (x^2)/(15)+(y^2)/(15)-(2x)/(15)-6/15 =0 ?

The solution to (x^2)/(15)+(y^2)/(15)-(2x)/(15)-6/15 =0 is Circle with (a,b)=(1,0),r=sqrt(7)

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(x^2)/(15)+(y^2)/(15)-(2x)/(15)-6/15 =0

\frac{x ^{2}}{15} + \frac{y ^{2}}{15} - \frac{2 x}{15} - \frac{6}{15} = 0

(a, b) = (1, 0), r = 7

Solution steps

\frac{x ^{2}}{15} + \frac{y ^{2}}{15} - \frac{2 x}{15} - \frac{6}{15} = 0

Rewrite

\frac{x ^{2}}{15} + \frac{y ^{2}}{15} - \frac{2 x}{15} - \frac{6}{15} = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 7

(x - 7)^{2} + (y + 13)^{2} = 81

x^{2} - 7 x + y^{2} - y - 2 = 0

(x - 8)^{2} + (y - 3)^{2} = 3

(x^{2} + 5 x + \frac{25}{4}) + y^{2} = \frac{25}{4} + \frac{25}{4}

x^{2} + y^{2} + 8 x + 6 y + 9 = 0

What is (x^2)/(15)+(y^2)/(15)-(2x)/(15)-6/15 =0 ?
The solution to (x^2)/(15)+(y^2)/(15)-(2x)/(15)-6/15 =0 is Circle with (a,b)=(1,0),r=sqrt(7)