What is x^2-7x+y^2-y-2=0 ?

The solution to x^2-7x+y^2-y-2=0 is Circle with (a,b)=(7/2 , 1/2),r=sqrt(29/2)

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x^2-7x+y^2-y-2=0

x^{2} - 7 x + y^{2} - y - 2 = 0

(a, b) = (\frac{7}{2}, \frac{1}{2}), r = \frac{29}{2}

Solution steps

x^{2} - 7 x + y^{2} - y - 2 = 0

Rewrite

x^{2} - 7 x + y^{2} - y - 2 = 0

in the form of the standard circle equation

(x - \frac{7}{2})^{2} + (y - \frac{1}{2})^{2} = (\frac{29}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{7}{2}, \frac{1}{2}), r = \frac{29}{2}

(x - 8)^{2} + (y - 3)^{2} = 3

(x^{2} + 5 x + \frac{25}{4}) + y^{2} = \frac{25}{4} + \frac{25}{4}

x^{2} + y^{2} + 8 x + 6 y + 9 = 0

x^{2} + y^{2} + 4 x - 2 y - 5 = 0

a^{2} + b^{2} = 15.5 6^{2}

What is x^2-7x+y^2-y-2=0 ?
The solution to x^2-7x+y^2-y-2=0 is Circle with (a,b)=(7/2 , 1/2),r=sqrt(29/2)