What is 2x^2+2y^2+3x-2y-43=0 ?

The solution to 2x^2+2y^2+3x-2y-43=0 is Circle with (a,b)=(-3/4 , 1/2),r=(sqrt(357))/4

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2x^2+2y^2+3x-2y-43=0

2 x^{2} + 2 y^{2} + 3 x - 2 y - 43 = 0

(a, b) = (- \frac{3}{4}, \frac{1}{2}), r = \frac{357}{4}

Solution steps

2 x^{2} + 2 y^{2} + 3 x - 2 y - 43 = 0

Rewrite

2 x^{2} + 2 y^{2} + 3 x - 2 y - 43 = 0

in the form of the standard circle equation

(x - (- \frac{3}{4}))^{2} + (y - \frac{1}{2})^{2} = (\frac{357}{4})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{4}, \frac{1}{2}), r = \frac{357}{4}

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2 x^{2} - 8 x + 8 + 2 y^{2} + 4 x + 2 = 25

100 = x^{2} + y^{2} + 4 x + 60

(x + 3)^{2} + (y + 3)^{2} = 25

What is 2x^2+2y^2+3x-2y-43=0 ?
The solution to 2x^2+2y^2+3x-2y-43=0 is Circle with (a,b)=(-3/4 , 1/2),r=(sqrt(357))/4