What is 100=x^2+y^2+4x+60 ?

The solution to 100=x^2+y^2+4x+60 is Circle with (a,b)=(-2,0),r=2sqrt(11)

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100=x^2+y^2+4x+60

100 = x^{2} + y^{2} + 4 x + 60

(a, b) = (- 2, 0), r = 211

Solution steps

100 = x^{2} + y^{2} + 4 x + 60

Rewrite

100 = x^{2} + y^{2} + 4 x + 60

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = (211)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 211

(x + 3)^{2} + (y + 3)^{2} = 25

(x - 8)^{2} + (y - 3)^{2} = 9

(x - 4.5)^{2} + (y - 1.5)^{2} = 5.52

x^{2} + y^{2} + 2 x + 1 < 1

4 x^{2} + 4 y^{2} - 9 = 0

What is 100=x^2+y^2+4x+60 ?
The solution to 100=x^2+y^2+4x+60 is Circle with (a,b)=(-2,0),r=2sqrt(11)