What is (x^2)/(2^2)+(y^2)/(2^2)=1 ?

The solution to (x^2)/(2^2)+(y^2)/(2^2)=1 is Circle with (a,b)=(0,0),r=2

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(x^2)/(2^2)+(y^2)/(2^2)=1

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{2 ^{2}} = 1

(a, b) = (0, 0), r = 2

Solution steps

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{2 ^{2}} = 1

Rewrite

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{2 ^{2}} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + y^{2} + 10 x + 20 y + 77 = 0

(x - (- 3))^{2} + (y - 5)^{2} = 4

y^{2} = - x^{2} + 100

x^{2} + y^{2} = 4 x - 3 y

x^{2} + y^{2} = 1 1^{2}

What is (x^2)/(2^2)+(y^2)/(2^2)=1 ?
The solution to (x^2)/(2^2)+(y^2)/(2^2)=1 is Circle with (a,b)=(0,0),r=2