What is (x-(-3))^2+(y-5)^2=4 ?

The solution to (x-(-3))^2+(y-5)^2=4 is Circle with (a,b)=(-3,5),r=2

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(x-(-3))^2+(y-5)^2=4

(x - (- 3))^{2} + (y - 5)^{2} = 4

(a, b) = (- 3, 5), r = 2

Solution steps

(x - (- 3))^{2} + (y - 5)^{2} = 4

Rewrite

(x - (- 3))^{2} + (y - 5)^{2} = 4

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 5)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 3, 5), r = 2

y^{2} = - x^{2} + 100

x^{2} + y^{2} = 4 x - 3 y

x^{2} + y^{2} = 1 1^{2}

x^{2} + y^{2} - 3 x = 39 - 6 y

x^{(2)} + (y - 4)^{(2)} = 16

What is (x-(-3))^2+(y-5)^2=4 ?
The solution to (x-(-3))^2+(y-5)^2=4 is Circle with (a,b)=(-3,5),r=2