What is x^2+y^2-x=2 ?

The solution to x^2+y^2-x=2 is Circle with (a,b)=(1/2 ,0),r= 3/2

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x^2+y^2-x=2

x^{2} + y^{2} - x = 2

(a, b) = (\frac{1}{2}, 0), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} - x = 2

Rewrite

x^{2} + y^{2} - x = 2

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = \frac{3}{2}

(x - 4)^{(2)} + (y + 10)^{(2)} = 144

x^{2} + 6 x + 9 + y^{2} - 2 y + 1 = 54 + 9 + 1

x^{2} = - y^{2} + 10 y + 5

(x - (- 4))^{2} + (y - (2))^{2} = 3^{2}

(x - 12)^{2} + y^{2} = 144

What is x^2+y^2-x=2 ?
The solution to x^2+y^2-x=2 is Circle with (a,b)=(1/2 ,0),r= 3/2