What is 2x^2+x+2y^2=6 ?

The solution to 2x^2+x+2y^2=6 is Circle with (a,b)=(-1/4 ,0),r= 7/4

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2x^2+x+2y^2=6

2 x^{2} + x + 2 y^{2} = 6

(a, b) = (- \frac{1}{4}, 0), r = \frac{7}{4}

Solution steps

2 x^{2} + x + 2 y^{2} = 6

Rewrite

2 x^{2} + x + 2 y^{2} = 6

in the form of the standard circle equation

(x - (- \frac{1}{4}))^{2} + (y - 0)^{2} = (\frac{7}{4})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{4}, 0), r = \frac{7}{4}

z^{2} = 1 - y^{2}

(x - 9)^{2} + y^{2} = 2

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

2 x^{2} + 2 y^{2} = 100

(x + 0)^{2} + (y + 0)^{2} = 25

What is 2x^2+x+2y^2=6 ?
The solution to 2x^2+x+2y^2=6 is Circle with (a,b)=(-1/4 ,0),r= 7/4