What is (x+2)^2+(y-1.5)^2=(sqrt(2.75)i)^2 ?

The solution to (x+2)^2+(y-1.5)^2=(sqrt(2.75)i)^2 is Circle with (a,b)=(-2,1.5),r=1.65831…i

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(x+2)^2+(y-1.5)^2=(sqrt(2.75)i)^2

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

(a, b) = (- 2, 1.5), r = 1.65831 \dots i

Solution steps

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

Rewrite

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1.5)^{2} = (1.65831 \dots i)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1.5), r = 1.65831 \dots i

2 x^{2} + 2 y^{2} = 100

(x + 0)^{2} + (y + 0)^{2} = 25

(x + 0)^{2} + (y + 0)^{2} = 17

(x - 15)^{2} + (y + 7)^{2} = 1 5^{2}

x^{2} + y^{2} + 6 x + 8 y - 11 = 0

What is (x+2)^2+(y-1.5)^2=(sqrt(2.75)i)^2 ?
The solution to (x+2)^2+(y-1.5)^2=(sqrt(2.75)i)^2 is Circle with (a,b)=(-2,1.5),r=1.65831…i