What is (x+5)^2+(y+1)^2=36 ?

The solution to (x+5)^2+(y+1)^2=36 is Circle with (a,b)=(-5,-1),r=6

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(x+5)^2+(y+1)^2=36

(x + 5)^{2} + (y + 1)^{2} = 36

(a, b) = (- 5, - 1), r = 6

Solution steps

(x + 5)^{2} + (y + 1)^{2} = 36

Rewrite

(x + 5)^{2} + (y + 1)^{2} = 36

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 1))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 1), r = 6

(x + 7)^{2} + (y - 1)^{2} = 225

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

(x + 1)^{2} + (y - 3)^{2} = 2^{2}

x^{2} + 6 x + y^{2} - 2 y + 1 = 0

x^{2} + y^{2} - x - 2 y + \frac{1}{4} = 0

What is (x+5)^2+(y+1)^2=36 ?
The solution to (x+5)^2+(y+1)^2=36 is Circle with (a,b)=(-5,-1),r=6