What is x^2+14x+49+y^2-14y+49=49 ?

The solution to x^2+14x+49+y^2-14y+49=49 is Circle with (a,b)=(-7,7),r=7

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x^2+14x+49+y^2-14y+49=49

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

(a, b) = (- 7, 7), r = 7

Solution steps

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

Rewrite

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 7)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, 7), r = 7

(x + 1)^{2} + (y - 3)^{2} = 2^{2}

x^{2} + 6 x + y^{2} - 2 y + 1 = 0

x^{2} + y^{2} - x - 2 y + \frac{1}{4} = 0

1000 = 200 (1 + x^{2} + y^{2})

x^{2} + y^{2} + 12 x - 16 y - 1 = 0

What is x^2+14x+49+y^2-14y+49=49 ?
The solution to x^2+14x+49+y^2-14y+49=49 is Circle with (a,b)=(-7,7),r=7