What is 1000=200(1+x^2+y^2) ?

The solution to 1000=200(1+x^2+y^2) is Circle with (a,b)=(0,0),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1000=200(1+x^2+y^2)

1000 = 200 (1 + x^{2} + y^{2})

(a, b) = (0, 0), r = 2

Solution steps

1000 = 200 (1 + x^{2} + y^{2})

Rewrite

1000 = 200 (1 + x^{2} + y^{2})

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + y^{2} + 12 x - 16 y - 1 = 0

x^{2} + y^{2} + 2 x + 2 y + 8 - 36 = 0

x^{2} + y^{2} + 4 x - 6 y - 36 = 0

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 1

x^{2} + y^{2} - 34 = 3 x

What is 1000=200(1+x^2+y^2) ?
The solution to 1000=200(1+x^2+y^2) is Circle with (a,b)=(0,0),r=2