What is 5x^2+x+5y^2-y-9=0 ?

The solution to 5x^2+x+5y^2-y-9=0 is Circle with (a,b)=(-1/10 , 1/10),r=(sqrt(91))/(5sqrt(2))

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5x^2+x+5y^2-y-9=0

5 x^{2} + x + 5 y^{2} - y - 9 = 0

(a, b) = (- \frac{1}{10}, \frac{1}{10}), r = \frac{91}{5 2}

Solution steps

5 x^{2} + x + 5 y^{2} - y - 9 = 0

Rewrite

5 x^{2} + x + 5 y^{2} - y - 9 = 0

in the form of the standard circle equation

(x - (- \frac{1}{10}))^{2} + (y - \frac{1}{10})^{2} = (\frac{91}{5 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{10}, \frac{1}{10}), r = \frac{91}{5 2}

x^{2} - 4 x + y^{2} - 6 y = 3

(x - 9)^{2} + (y - 2)^{2} = 25

(x + 9)^{2} + (y - 3)^{2} = 80

x^{2} + y^{2} + 4 x - 20 y + 40 = 0

(y + 4)^{2} + (x - 3)^{2} = 104

What is 5x^2+x+5y^2-y-9=0 ?
The solution to 5x^2+x+5y^2-y-9=0 is Circle with (a,b)=(-1/10 , 1/10),r=(sqrt(91))/(5sqrt(2))