What is (x+9)^2+(y-3)^2=80 ?

The solution to (x+9)^2+(y-3)^2=80 is Circle with (a,b)=(-9,3),r=sqrt(80)

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(x+9)^2+(y-3)^2=80

(x + 9)^{2} + (y - 3)^{2} = 80

(a, b) = (- 9, 3), r = 80

Solution steps

(x + 9)^{2} + (y - 3)^{2} = 80

Rewrite

(x + 9)^{2} + (y - 3)^{2} = 80

in the form of the standard circle equation

(x - (- 9))^{2} + (y - 3)^{2} = (80)^{2}

Therefore the circle properties are:

(a, b) = (- 9, 3), r = 80

x^{2} + y^{2} + 4 x - 20 y + 40 = 0

(y + 4)^{2} + (x - 3)^{2} = 104

x^{2} + y^{2} - 4 x + 6 y - 6 = 0

\frac{( x + 5 ) ^{2}}{4} + \frac{( y ) ^{2}}{4} = 1

(x - 2)^{2} + y^{2} = 100

What is (x+9)^2+(y-3)^2=80 ?
The solution to (x+9)^2+(y-3)^2=80 is Circle with (a,b)=(-9,3),r=sqrt(80)