What is x^2+y^2-4x+6y-6=0 ?

The solution to x^2+y^2-4x+6y-6=0 is Circle with (a,b)=(2,-3),r=sqrt(19)

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x^2+y^2-4x+6y-6=0

x^{2} + y^{2} - 4 x + 6 y - 6 = 0

(a, b) = (2, - 3), r = 19

Solution steps

x^{2} + y^{2} - 4 x + 6 y - 6 = 0

Rewrite

x^{2} + y^{2} - 4 x + 6 y - 6 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (19)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 19

\frac{( x + 5 ) ^{2}}{4} + \frac{( y ) ^{2}}{4} = 1

(x - 2)^{2} + y^{2} = 100

x^{2} - 4 x + y^{2} - 2 y = 11

x^{2} + y^{2} + 4 x + 8 y - 36 = 0

x^{2} + y^{2} - 6 x - 8 y - 22 = 0

What is x^2+y^2-4x+6y-6=0 ?
The solution to x^2+y^2-4x+6y-6=0 is Circle with (a,b)=(2,-3),r=sqrt(19)