What is x^2-4x+y^2-2y=11 ?

The solution to x^2-4x+y^2-2y=11 is Circle with (a,b)=(2,1),r=4

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x^2-4x+y^2-2y=11

x^{2} - 4 x + y^{2} - 2 y = 11

(a, b) = (2, 1), r = 4

Solution steps

x^{2} - 4 x + y^{2} - 2 y = 11

Rewrite

x^{2} - 4 x + y^{2} - 2 y = 11

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 4

x^{2} + y^{2} + 4 x + 8 y - 36 = 0

x^{2} + y^{2} - 6 x - 8 y - 22 = 0

x^{2} + y^{2} - 9 x - 2 y + 17 = 0

x^{2} + y^{2} - 12 x + 8 y + 47 = 0

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

What is x^2-4x+y^2-2y=11 ?
The solution to x^2-4x+y^2-2y=11 is Circle with (a,b)=(2,1),r=4