What is (x-1)^2+(y-2)^2=(2sqrt(2))^2 ?

The solution to (x-1)^2+(y-2)^2=(2sqrt(2))^2 is Circle with (a,b)=(1,2),r=sqrt((2\sqrt{2))^2}

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(x-1)^2+(y-2)^2=(2sqrt(2))^2

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

(a, b) = (1, 2), r = (22)^{2}

Solution steps

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

Rewrite

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = ((22)^{2})^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = (22)^{2}

x^{2} - 6 x + y^{2} - 4 y = - 9

(x - 10)^{2} + (y - 5)^{2} = 28

f (x) (f (x)) = - x^{2} + 3 x

x^{2} - 6 x + y^{2} - 4 y = - 4

x^{2} + y^{2} - 18 x + 12 y + 80 = 0

What is (x-1)^2+(y-2)^2=(2sqrt(2))^2 ?
The solution to (x-1)^2+(y-2)^2=(2sqrt(2))^2 is Circle with (a,b)=(1,2),r=sqrt((2\sqrt{2))^2}