What is f(x)(f(x))=-x^2+3x ?

The solution to f(x)(f(x))=-x^2+3x is Circle with (a,b)=(3/2 ,0),r= 3/2

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f(x)(f(x))=-x^2+3x

f (x) (f (x)) = - x^{2} + 3 x

(a, b) = (\frac{3}{2}, 0), r = \frac{3}{2}

Solution steps

yy = - x^{2} + 3 x

Rewrite

yy = - x^{2} + 3 x

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 0)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 0), r = \frac{3}{2}

x^{2} - 6 x + y^{2} - 4 y = - 4

x^{2} + y^{2} - 18 x + 12 y + 80 = 0

x^{2} + y^{2} = x - y

x^{2} + y^{2} - 280 x + 4244 y + 464 = 0

x^{2} - 4 x + y^{2} - 10 y = - 20

What is f(x)(f(x))=-x^2+3x ?
The solution to f(x)(f(x))=-x^2+3x is Circle with (a,b)=(3/2 ,0),r= 3/2