What is x^2+y^2-280x+4244y+464=0 ?

The solution to x^2+y^2-280x+4244y+464=0 is Circle with (a,b)=(140,-2122),r=2sqrt(1130505)

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x^2+y^2-280x+4244y+464=0

x^{2} + y^{2} - 280 x + 4244 y + 464 = 0

(a, b) = (140, - 2122), r = 21130505

Solution steps

x^{2} + y^{2} - 280 x + 4244 y + 464 = 0

Rewrite

x^{2} + y^{2} - 280 x + 4244 y + 464 = 0

in the form of the standard circle equation

(x - 140)^{2} + (y - (- 2122))^{2} = (21130505)^{2}

Therefore the circle properties are:

(a, b) = (140, - 2122), r = 21130505

x^{2} - 4 x + y^{2} - 10 y = - 20

x^{2} + y^{2} - 6 x - 8 y - 35 = 0

x^{2} - 4 x + y^{2} - 10 y = - 28

4 x^{2} + 8 x + 4 y^{2} - 12 y = 51

x^{2} + y^{2} - 12 x = - 35

What is x^2+y^2-280x+4244y+464=0 ?
The solution to x^2+y^2-280x+4244y+464=0 is Circle with (a,b)=(140,-2122),r=2sqrt(1130505)