What is x^2+y^2-6x-8y-35=0 ?

The solution to x^2+y^2-6x-8y-35=0 is Circle with (a,b)=(3,4),r=2sqrt(15)

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x^2+y^2-6x-8y-35=0

x^{2} + y^{2} - 6 x - 8 y - 35 = 0

(a, b) = (3, 4), r = 215

Solution steps

x^{2} + y^{2} - 6 x - 8 y - 35 = 0

Rewrite

x^{2} + y^{2} - 6 x - 8 y - 35 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = (215)^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 215

x^{2} - 4 x + y^{2} - 10 y = - 28

4 x^{2} + 8 x + 4 y^{2} - 12 y = 51

x^{2} + y^{2} - 12 x = - 35

x^{2} + y^{2} + (- 6) + 4 y - 3 = 0

x^{2} - 14 x + y^{2} + 10 y + 58 = 0

What is x^2+y^2-6x-8y-35=0 ?
The solution to x^2+y^2-6x-8y-35=0 is Circle with (a,b)=(3,4),r=2sqrt(15)