What is x^2-14x+y^2+10y+58=0 ?

The solution to x^2-14x+y^2+10y+58=0 is Circle with (a,b)=(7,-5),r=4

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x^2-14x+y^2+10y+58=0

x^{2} - 14 x + y^{2} + 10 y + 58 = 0

(a, b) = (7, - 5), r = 4

Solution steps

x^{2} - 14 x + y^{2} + 10 y + 58 = 0

Rewrite

x^{2} - 14 x + y^{2} + 10 y + 58 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (7, - 5), r = 4

(x - (- 3))^{2} + (y - 4)^{2} = 5^{2}

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

x^{2} + y^{2} + 8 x + 4 y - 5 = 0

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

(x^{2} + 3 x) + (y^{2} - 4 y) = 6

What is x^2-14x+y^2+10y+58=0 ?
The solution to x^2-14x+y^2+10y+58=0 is Circle with (a,b)=(7,-5),r=4