What is 4x^2+8x+4y^2-12y=23 ?

The solution to 4x^2+8x+4y^2-12y=23 is Circle with (a,b)=(-1, 3/2),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+8x+4y^2-12y=23

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

(a, b) = (- 1, \frac{3}{2}), r = 3

Solution steps

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

Rewrite

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{3}{2})^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{3}{2}), r = 3

x^{2} + y^{2} + 8 x + 4 y - 5 = 0

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

(x^{2} + 3 x) + (y^{2} - 4 y) = 6

2 x^{2} + 2 y^{2} - 2 x + 4 y = 45

2 x^{(2)} + 2 y^{(2)} - 4 x + 12 y - 12 = 0

What is 4x^2+8x+4y^2-12y=23 ?
The solution to 4x^2+8x+4y^2-12y=23 is Circle with (a,b)=(-1, 3/2),r=3