What is x^2+y^2-2x-15+14y=0 ?

The solution to x^2+y^2-2x-15+14y=0 is Circle with (a,b)=(1,-7),r=sqrt(65)

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x^2+y^2-2x-15+14y=0

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

(a, b) = (1, - 7), r = 65

Solution steps

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

Rewrite

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 7))^{2} = (65)^{2}

Therefore the circle properties are:

(a, b) = (1, - 7), r = 65

(x^{2} + 3 x) + (y^{2} - 4 y) = 6

2 x^{2} + 2 y^{2} - 2 x + 4 y = 45

2 x^{(2)} + 2 y^{(2)} - 4 x + 12 y - 12 = 0

x^{2} + y^{2} + 8 x + 8 y = - 16

3 x^{2} + 6 y + 3 y^{2} + 5 x - 15 = 0

What is x^2+y^2-2x-15+14y=0 ?
The solution to x^2+y^2-2x-15+14y=0 is Circle with (a,b)=(1,-7),r=sqrt(65)