What is 3x^2+6y+3y^2+5x-15=0 ?

The solution to 3x^2+6y+3y^2+5x-15=0 is Circle with (a,b)=(-5/6 ,-1),r=(sqrt(241))/6

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3x^2+6y+3y^2+5x-15=0

3 x^{2} + 6 y + 3 y^{2} + 5 x - 15 = 0

(a, b) = (- \frac{5}{6}, - 1), r = \frac{241}{6}

Solution steps

3 x^{2} + 6 y + 3 y^{2} + 5 x - 15 = 0

Rewrite

3 x^{2} + 6 y + 3 y^{2} + 5 x - 15 = 0

in the form of the standard circle equation

(x - (- \frac{5}{6}))^{2} + (y - (- 1))^{2} = (\frac{241}{6})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{6}, - 1), r = \frac{241}{6}

x^{2} + y^{2} - 2 x + 4 y = 11

x^{2} + y^{2} - x + 3 y - \frac{15}{4} = 0

x^{2} + y^{2} + 6 x - 10 y - 2 = 0

(x + \frac{1}{2})^{2} + (y + 3)^{2} = \frac{1}{2 ^{2}}

x^{2} + 4 x + y^{2} + 4 y - 8 = 0

What is 3x^2+6y+3y^2+5x-15=0 ?
The solution to 3x^2+6y+3y^2+5x-15=0 is Circle with (a,b)=(-5/6 ,-1),r=(sqrt(241))/6