What is x^2+y^2-4y-15=6 ?

The solution to x^2+y^2-4y-15=6 is Circle with (a,b)=(0,2),r=5

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x^2+y^2-4y-15=6

x^{2} + y^{2} - 4 y - 15 = 6

(a, b) = (0, 2), r = 5

Solution steps

x^{2} + y^{2} - 4 y - 15 = 6

Rewrite

x^{2} + y^{2} - 4 y - 15 = 6

in the form of the standard circle equation

(x - 0)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 2), r = 5

x^{2} + (y + 1)^{2} = 2^{2}

5 0^{2} = (x - 21.21)^{2} + (y - 21.21)^{2}

x^{2} + y^{2} - 4 x - 14 y + 50 = 0

9 x^{2} + 9 y^{2} + 72 y + 36 y + 155 = 0

(x + 1)^{2} + (y - 2)^{2} = 36

What is x^2+y^2-4y-15=6 ?
The solution to x^2+y^2-4y-15=6 is Circle with (a,b)=(0,2),r=5