What is 50^2=(x-21.21)^2+(y-21.21)^2 ?

The solution to 50^2=(x-21.21)^2+(y-21.21)^2 is Circle with (a,b)=(21.21,21.21),r=50

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50^2=(x-21.21)^2+(y-21.21)^2

5 0^{2} = (x - 21.21)^{2} + (y - 21.21)^{2}

(a, b) = (21.21, 21.21), r = 50

Solution steps

5 0^{2} = (x - 21.21)^{2} + (y - 21.21)^{2}

Rewrite

5 0^{2} = (x - 21.21)^{2} + (y - 21.21)^{2}

in the form of the standard circle equation

(x - 21.21)^{2} + (y - 21.21)^{2} = 5 0^{2}

Therefore the circle properties are:

(a, b) = (21.21, 21.21), r = 50

x^{2} + y^{2} - 4 x - 14 y + 50 = 0

9 x^{2} + 9 y^{2} + 72 y + 36 y + 155 = 0

(x + 1)^{2} + (y - 2)^{2} = 36

(x + 7)^{2} + (y + 4)^{2} = 3

x^{2} + y^{2} + 10 x + 8 y - 11 = 0

What is 50^2=(x-21.21)^2+(y-21.21)^2 ?
The solution to 50^2=(x-21.21)^2+(y-21.21)^2 is Circle with (a,b)=(21.21,21.21),r=50