What is (x+7)^2+(y+4)^2=3 ?

The solution to (x+7)^2+(y+4)^2=3 is Circle with (a,b)=(-7,-4),r=sqrt(3)

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(x+7)^2+(y+4)^2=3

(x + 7)^{2} + (y + 4)^{2} = 3

(a, b) = (- 7, - 4), r = 3

Solution steps

(x + 7)^{2} + (y + 4)^{2} = 3

Rewrite

(x + 7)^{2} + (y + 4)^{2} = 3

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 4))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 4), r = 3

x^{2} + y^{2} + 10 x + 8 y - 11 = 0

(x - 5)^{2} + (y + 2)^{2} - 85 = 0

x^{2} + y^{2} + 4 x - 3 y = 9

x^{2} + y^{2} + 16 x + 8 y + 71 = 0

(x + 1)^{2} + (y - 2)^{2} = 20

What is (x+7)^2+(y+4)^2=3 ?
The solution to (x+7)^2+(y+4)^2=3 is Circle with (a,b)=(-7,-4),r=sqrt(3)