What is x^2+y^2+4x-3y=9 ?

The solution to x^2+y^2+4x-3y=9 is Circle with (a,b)=(-2, 3/2),r=(sqrt(61))/2

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x^2+y^2+4x-3y=9

x^{2} + y^{2} + 4 x - 3 y = 9

(a, b) = (- 2, \frac{3}{2}), r = \frac{61}{2}

Solution steps

x^{2} + y^{2} + 4 x - 3 y = 9

Rewrite

x^{2} + y^{2} + 4 x - 3 y = 9

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{3}{2})^{2} = (\frac{61}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{3}{2}), r = \frac{61}{2}

x^{2} + y^{2} + 16 x + 8 y + 71 = 0

(x + 1)^{2} + (y - 2)^{2} = 20

x^{2} + y^{2} - 6 x - 2 y + 5 = 0

x^{2} + y^{2} + 12 x + 4 y - 9 = 0

x^{2} + y^{2} - 16 x + 2 y + 5 = 0

What is x^2+y^2+4x-3y=9 ?
The solution to x^2+y^2+4x-3y=9 is Circle with (a,b)=(-2, 3/2),r=(sqrt(61))/2