What is (x+1)^2+(y-2)^2=20 ?

The solution to (x+1)^2+(y-2)^2=20 is Circle with (a,b)=(-1,2),r=sqrt(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+1)^2+(y-2)^2=20

(x + 1)^{2} + (y - 2)^{2} = 20

(a, b) = (- 1, 2), r = 20

Solution steps

(x + 1)^{2} + (y - 2)^{2} = 20

Rewrite

(x + 1)^{2} + (y - 2)^{2} = 20

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = (20)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 20

x^{2} + y^{2} - 6 x - 2 y + 5 = 0

x^{2} + y^{2} + 12 x + 4 y - 9 = 0

x^{2} + y^{2} - 16 x + 2 y + 5 = 0

(x + 1)^{2} + (y - 2)^{2} = 12

(12)^{2} + 8 = x^{2} + y^{2}

What is (x+1)^2+(y-2)^2=20 ?
The solution to (x+1)^2+(y-2)^2=20 is Circle with (a,b)=(-1,2),r=sqrt(20)