What is (12)^2+8=x^2+y^2 ?

The solution to (12)^2+8=x^2+y^2 is Circle with (a,b)=(0,0),r=2sqrt(38)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(12)^2+8=x^2+y^2

(12)^{2} + 8 = x^{2} + y^{2}

(a, b) = (0, 0), r = 238

Solution steps

1 2^{2} + 8 = x^{2} + y^{2}

Rewrite

1 2^{2} + 8 = x^{2} + y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (238)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 238

(x + 1)^{2} + (y + 1)^{2} = 6

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

4 x^{2} + 12 x + 4 y^{2} + 16 y + 11 = 0

(x + 5)^{2} + (y + 6)^{2} = 12

x^{2} + y^{2} - x - y - 16 = 0

What is (12)^2+8=x^2+y^2 ?
The solution to (12)^2+8=x^2+y^2 is Circle with (a,b)=(0,0),r=2sqrt(38)