What is (x-(-7))^2+(y-(-4))^2=7^2 ?

The solution to (x-(-7))^2+(y-(-4))^2=7^2 is Circle with (a,b)=(-7,-4),r=7

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(x-(-7))^2+(y-(-4))^2=7^2

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

(a, b) = (- 7, - 4), r = 7

Solution steps

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

Rewrite

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 4), r = 7

4 x^{2} + 12 x + 4 y^{2} + 16 y + 11 = 0

(x + 5)^{2} + (y + 6)^{2} = 12

x^{2} + y^{2} - x - y - 16 = 0

(x^{2} + 2 x) + (y^{2} + 4 y) = - 1

x^{2} + y^{2} - 4 x - 6 y - 36 = 0

What is (x-(-7))^2+(y-(-4))^2=7^2 ?
The solution to (x-(-7))^2+(y-(-4))^2=7^2 is Circle with (a,b)=(-7,-4),r=7