What is 0.38^2=(x+1.7)^2+(y+0.5)^2 ?

The solution to 0.38^2=(x+1.7)^2+(y+0.5)^2 is Circle with (a,b)=(-1.7,-1/2),r=0.38

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0.38^2=(x+1.7)^2+(y+0.5)^2

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

(a, b) = (- 1.7, - \frac{1}{2}), r = 0.38

Solution steps

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

Rewrite

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

in the form of the standard circle equation

(x - (- 1.7))^{2} + (y - (- \frac{1}{2}))^{2} = 0.3 8^{2}

Therefore the circle properties are:

(a, b) = (- 1.7, - \frac{1}{2}), r = 0.38

4 x^{2} - 4 + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - \frac{3}{2} x + \frac{2}{3} y - \frac{239}{36} = 0

[x - (- 3)]^{2} + (y - 1)^{2} = 1 0^{2}

x^{2} + y^{2} + 18 x = - 80

x^{2} + y^{2} > \frac{1}{2}

What is 0.38^2=(x+1.7)^2+(y+0.5)^2 ?
The solution to 0.38^2=(x+1.7)^2+(y+0.5)^2 is Circle with (a,b)=(-1.7,-1/2),r=0.38