What is [x-(-3)]^2+(y-1)^2=10^2 ?

The solution to [x-(-3)]^2+(y-1)^2=10^2 is Circle with (a,b)=(-3,1),r=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

[x-(-3)]^2+(y-1)^2=10^2

[x - (- 3)]^{2} + (y - 1)^{2} = 1 0^{2}

(a, b) = (- 3, 1), r = 10

Solution steps

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

Rewrite

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 10

x^{2} + y^{2} + 18 x = - 80

x^{2} + y^{2} > \frac{1}{2}

x^{2} - 8 x + y^{2} - 4 y + 10 = 0

x^{2} + x + y^{2} = 16

x^{2} + y^{2} - \frac{608}{79} x - \frac{1386}{79} y - \frac{5640}{79} = 0

What is [x-(-3)]^2+(y-1)^2=10^2 ?
The solution to [x-(-3)]^2+(y-1)^2=10^2 is Circle with (a,b)=(-3,1),r=10