What is x^2+x+y^2=16 ?

The solution to x^2+x+y^2=16 is Circle with (a,b)=(-1/2 ,0),r=(sqrt(65))/2

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x^2+x+y^2=16

x^{2} + x + y^{2} = 16

(a, b) = (- \frac{1}{2}, 0), r = \frac{65}{2}

Solution steps

x^{2} + x + y^{2} = 16

Rewrite

x^{2} + x + y^{2} = 16

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - 0)^{2} = (\frac{65}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, 0), r = \frac{65}{2}

x^{2} + y^{2} - \frac{608}{79} x - \frac{1386}{79} y - \frac{5640}{79} = 0

x^{(2)} + y^{(2)} + 4 x - 6 y + 12 = 0

(x + 1)^{2} + (y - 2)^{2} = 3^{2}

x^{2} - 2 x + y^{2} + 6 y - 6 = 0

x^{2} + y^{2} - x - 2 y - 1 = 0

What is x^2+x+y^2=16 ?
The solution to x^2+x+y^2=16 is Circle with (a,b)=(-1/2 ,0),r=(sqrt(65))/2