What is x^2-2x+y^2+6y-6=0 ?

The solution to x^2-2x+y^2+6y-6=0 is Circle with (a,b)=(1,-3),r=4

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x^2-2x+y^2+6y-6=0

x^{2} - 2 x + y^{2} + 6 y - 6 = 0

(a, b) = (1, - 3), r = 4

Solution steps

x^{2} - 2 x + y^{2} + 6 y - 6 = 0

Rewrite

x^{2} - 2 x + y^{2} + 6 y - 6 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 4

x^{2} + y^{2} - x - 2 y - 1 = 0

x (x + 5) + (y - 2)^{2} = 0

(x + 3)^{2} + (y - 3)^{2} = 25

x^{2} + y^{2} + 14 x - 2 y = 225

- x^{2} - y^{2} + 5 = x + y + 1

What is x^2-2x+y^2+6y-6=0 ?
The solution to x^2-2x+y^2+6y-6=0 is Circle with (a,b)=(1,-3),r=4