What is x^2+y^2+8x+12y=0 ?

The solution to x^2+y^2+8x+12y=0 is Circle with (a,b)=(-4,-6),r=2sqrt(13)

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x^2+y^2+8x+12y=0

x^{2} + y^{2} + 8 x + 12 y = 0

(a, b) = (- 4, - 6), r = 213

Solution steps

x^{2} + y^{2} + 8 x + 12 y = 0

Rewrite

x^{2} + y^{2} + 8 x + 12 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 6))^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 6), r = 213

(x + 3)^{2} + (y - 4)^{2} = 7

(x - 2)^{2} + (y + 2)^{2} = 20

(x - 2)^{2} + (y + 2)^{2} = 25

(x + 1)^{2} + (y - \frac{2}{3})^{2} = \frac{281}{3}^{2}

x^{2} + y^{2} + 8 y - 128 = 0

What is x^2+y^2+8x+12y=0 ?
The solution to x^2+y^2+8x+12y=0 is Circle with (a,b)=(-4,-6),r=2sqrt(13)