What is x^2+14x+y^2-2y+25=0 ?

The solution to x^2+14x+y^2-2y+25=0 is Circle with (a,b)=(-7,1),r=5

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x^2+14x+y^2-2y+25=0

x^{2} + 14 x + y^{2} - 2 y + 25 = 0

(a, b) = (- 7, 1), r = 5

Solution steps

x^{2} + 14 x + y^{2} - 2 y + 25 = 0

Rewrite

x^{2} + 14 x + y^{2} - 2 y + 25 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 1)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 7, 1), r = 5

x^{2} - 8 y + 6 x + y^{2} - 30 = 0

x^{2} + y^{2} - 26 x + 2 y + 120 = 0

x^{2} + y^{2} - 8 x - 8 (2 x + 1) + 27 = 0

(x - 4)^{2} + (y - 7)^{2} = (13)^{2}

(x - 2)^{2} + (y + 7)^{2} = 16

What is x^2+14x+y^2-2y+25=0 ?
The solution to x^2+14x+y^2-2y+25=0 is Circle with (a,b)=(-7,1),r=5