What is 2x^2+24x+2y^2=0 ?

The solution to 2x^2+24x+2y^2=0 is Circle with (a,b)=(-6,0),r=6

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2x^2+24x+2y^2=0

2 x^{2} + 24 x + 2 y^{2} = 0

(a, b) = (- 6, 0), r = 6

Solution steps

2 x^{2} + 24 x + 2 y^{2} = 0

Rewrite

2 x^{2} + 24 x + 2 y^{2} = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 6, 0), r = 6

(x + 7)^{2} + (y + 3)^{2} = 9

x^{2} + y^{2} - 2 x - 8 y = 0

x^{(2)} + y^{(2)} - 6 x - 4 y - 9 = 0

\frac{8 x ^{2} - 12 x + 8 y ^{2} + 20 y + 17}{8} = 2

(x + 1)^{2} + (y - 4)^{2} = 16

What is 2x^2+24x+2y^2=0 ?
The solution to 2x^2+24x+2y^2=0 is Circle with (a,b)=(-6,0),r=6