What is (x+7)^2+(y+3)^2=9 ?

The solution to (x+7)^2+(y+3)^2=9 is Circle with (a,b)=(-7,-3),r=3

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(x+7)^2+(y+3)^2=9

(x + 7)^{2} + (y + 3)^{2} = 9

(a, b) = (- 7, - 3), r = 3

Solution steps

(x + 7)^{2} + (y + 3)^{2} = 9

Rewrite

(x + 7)^{2} + (y + 3)^{2} = 9

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 3), r = 3

x^{2} + y^{2} - 2 x - 8 y = 0

x^{(2)} + y^{(2)} - 6 x - 4 y - 9 = 0

\frac{8 x ^{2} - 12 x + 8 y ^{2} + 20 y + 17}{8} = 2

(x + 1)^{2} + (y - 4)^{2} = 16

x^{2} + (y - 3)^{2} = 100

What is (x+7)^2+(y+3)^2=9 ?
The solution to (x+7)^2+(y+3)^2=9 is Circle with (a,b)=(-7,-3),r=3