What is x^2+(y-3)^2=100 ?

The solution to x^2+(y-3)^2=100 is Circle with (a,b)=(0,3),r=10

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x^2+(y-3)^2=100

x^{2} + (y - 3)^{2} = 100

(a, b) = (0, 3), r = 10

Solution steps

x^{2} + (y - 3)^{2} = 100

Rewrite

x^{2} + (y - 3)^{2} = 100

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 10

(x - 15)^{2} + (y + 15)^{2} = 256

[5 (x + 4)]^{2} + 25 (y - 2)^{2} = 625

x^{2} - 1 = 0 - y^{2} + 1

- x^{2} - y^{2} = - 1

- x^{2} - y^{2} + 2 x - 3 y + \frac{3}{4} = 0

What is x^2+(y-3)^2=100 ?
The solution to x^2+(y-3)^2=100 is Circle with (a,b)=(0,3),r=10