What is [5(x+4)]^2+25(y-2)^2=625 ?

The solution to [5(x+4)]^2+25(y-2)^2=625 is Circle with (a,b)=(-4,2),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

[5(x+4)]^2+25(y-2)^2=625

[5 (x + 4)]^{2} + 25 (y - 2)^{2} = 625

(a, b) = (- 4, 2), r = 5

Solution steps

(5 (x + 4))^{2} + 25 (y - 2)^{2} = 625

Rewrite

(5 (x + 4))^{2} + 25 (y - 2)^{2} = 625

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 5

x^{2} - 1 = 0 - y^{2} + 1

- x^{2} - y^{2} = - 1

- x^{2} - y^{2} + 2 x - 3 y + \frac{3}{4} = 0

(x - 5)^{2} + (y + 2)^{2} = 15

(x + 1)^{2} + (y - 4)^{2} = 30

What is [5(x+4)]^2+25(y-2)^2=625 ?
The solution to [5(x+4)]^2+25(y-2)^2=625 is Circle with (a,b)=(-4,2),r=5